How many grams of potassium nitrate (KNO3) are

required to produce 5.00 g of potassium nitrite (KNO2)

according to the equation below?

2KNO3 - 2KNO2 + O2

5.94 g

Explanation:

Looking at the equation, for every 2 moles of KNO₃ added, 2 moles of KNO₂ are produced. This means that the moles produced will be equal to the moles consumed.

Convert grams of KNO₂ to moles using the molar mass (85.1 g/mol) and get 0.0588 moles of KNO₂.

Since moles of KNO₂ are equal to mole of KNO₃, 0.0588 moles of KNO₃ are required. Convert this to grams using the molar mass (101.1 g/mol) and get 5.94 g.