Number of grams of hcl that can react with 0.500 grams of Al (OH) 3

0.7g of HCl

Explanation:

First, let us write a balanced equation for the reaction between HCl and Al (OH) 3.

This is illustrated below:

Al (OH) 3 + 3HCl - > AlCl3 + 3H2O

Next, let us obtain the masses of Al (OH) 3 and HCl that reacted together according to the equation. This can be achieved as shown below:

Molar Mass of Al (OH) 3 = 27 + 3 (16+1)

= 27 + 3 (17) = 27 + 51 = 78g/mol.

Molar Mass of HCl = 1 + 35.5 = 36.5g/mol

Mass of HCl from the balanced equation = 3 x 36.5 = 109.5g

Now we can obtain the mass of HCl that would react with 0.5g of Al (OH) 3. This can be achieved as follow:

Al (OH) 3 + 3HCl - > AlCl3 + 3H2O

From the equation above,

78g of Al (OH) 3 reacted with 109.5g of HCl.

Therefore, 0.5g of Al (OH) 3 will react with = (0.5 x 109.5) / 78 = 0.7g of HCl