The highest pressure allowed in a detector allowed is 1.88kPa. How many atm (atmospheres) of pressure are in this?

Answer: 0.0186 atm

Explanation:

Pressure can be measured in the following units: Pascals (pa), atmosphere (Atm), Newton per metre square (Nm^-2).

In this case,

Pressure of detector = 1.88kPa

(Covert 1.88kPa to Pascal)

Recall that 1kPa = 1000Pa

1.88kPa = 1.88 x 1000 = 1880Pa

Now, convert 1880Pa to Atm

Recall that:

1 Atm = 101325 pascal (Pa).

Z Atm = 1880Pa

To get the value of Z, cross multiply

1880Pa x 1 Atm = 101325Pa x Z Atm

1880 = 101325Z

Divide both sides by 101325

1880/101325 = 101325Z/101325

0.0186 = Z

Thus, the 0.0186 atm (atmospheres) of pressure in 1.88kPa