How many grams of hydrogen are in "69" g of ch4o?

8.62 g of Hydrogen

Solution:

Molar mass of CH₄O (Methanol) is 32 g. mol⁻¹.

It means,

32 g of CH₄O contains = 4 g of Hydrogen

Then,

69 g of CH₄O will contain = X g of Hydrogen

Solving for X,

X = (69 g * 4 g) : 32 g

X = 8.62 g of Hydrogen