Given the balanced equation: 2 h2 (g) + o2 (g) → 2 h2o (l) how many grams of h2o are formed if 9.00 mol h2 (g) reacts completely with an excess of o2 (g) ? the molar mass of h2o is 18.0 g/mol.

162 g of H₂O

Solution:

The Balance Chemical Equation is as follow,

2 H₂ + O₂ → 2 H₂O

According to equation when,

2 mol of H₂ is reacted = 36 g (2 mol) H₂O is produced

So,

9 mol H₂ on reaction will produce = X g of H₂O

Solving for X,

X = (9 mol * 36 g) : 2 mol

X = 162 g of H₂O