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9 June, 07:29

How many moles of NaCl are present in a solution with a molarity of 8.59 M and a volume of 125 mL

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Answers (2)
  1. 9 June, 08:07
    0
    Moles = 1.07mol

    Explanation:

    C = 8.59M, V = 0.125dm3

    n = C*V

    n = 8.59*0.125 = 1.07mol
  2. 9 June, 08:33
    0
    1.07ML
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