A sample of air with a volume of 2.20m3 at a pressure of 105 KPa and a temperature of 30c is cooled to 10c and the pressure is reduced to 75.0 KPa.

What is the new volume?

6.9

1.34

2.56

43.0

2.88

Answer: The answer is 2.88 m3

Explanation: Since temperature, pressure and volume are given in the question, the general gas equation will be useful in calculating the new volume.

General gas equation,

(P1V1) / T1 = (P2V2) / T2 ... (1)

Where,

P1 = Initial pressure

P2 = Final pressure

V1 = Initial volume

V2 = Final volume

T1 = Initial temperature in kelvin

T2 = Final temperature in Kelvin

Hence, from the question:

P1 = 105 KPa = 105,000 Pa

P2 = 75 KPa = 75,000 Pa

V1 = 2.20 m3

V2 = ?

T1 = 30 °C = (273+30) K = 303 K

T2 = 10 °C = (273+10) K = 283 K

Therefore, substitute these value into the general gas equation as given in eq (1) above.

V2 = (P1V1T2) / P2V1

V2 = (105000*2.2*283) / (75000*303)

V2 = 2.88 m3

It would be 43.0

hope it's right sir