How much energy is needed to heat 20.0 grams of water from 25.0°C to 50.0 °C?

Yeah what he said is correct

The answer to your question is Q = 2093 J

Explanation:

Data

Energy = Q = ?

mass = 20 g

Temperature 1 = 25°C

Temperature 2 = 50°C

Specific heat = Cp = 4.186 J/g°C

Formula

Energy = Q = mCp (Temperature 2 - Temperature 1)

Substitution

Q = (20) (4.186) (50 - 25)

Simplification

Q = (20) (4.186) (25)

Result

Q = 2093 J