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24 August, 07:19

what was the initial pressure of 14.8 mL of gas at 75.5 C, when it occupied a volume of 16.5 mL at 70.2 C and 101.3 kPa?

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  1. 24 August, 10:31
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    1038.96 kPa

    Explanation:

    We'll use the ideal gas law; P1V1/T1 = P2V2/T2

    P1*14.8/75.5 = 101.3*16.5/70.2

    P1 = (101.3 * 16.5 * 75.5) / (70.2 * 14.8)

    P1 = 1038.96
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