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17 April, 06:01

What is the concentration (M) of CH3OH in a solution prepared by dissolving 12.5 g of CH3OH in sufficient water to give exactly 230 mL of solution?

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  1. 17 April, 09:39
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    1.7 M

    Explanation:

    Concentration is the number of moles of solute dissolved in 1 L of solution

    Concentration = number of moles of solute / volume of solution

    Number of moles of solute needs to be calculated first

    Mass of methanol - 12.5 g

    Molar mass of methanol - 32 g/mol

    Number of methanol moles - 12.5 g / 32 g/mol = 0.39 mol

    Therefore concentration is = 0.39 mol / 0.230 L = 1.7 mol/L

    Concentration is 1.7 M
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