How many liters does the following number of atoms of helium take up?

9.42x10^22 atoms He

3.50*10^253 L of Helium

Explanation:

I mole of He contains 1 atom

1 mole = 6.022 * 10^23 atoms

so 1 mole = 6.022*10^23

(9.42*10^22 / 6.022*10^23) = 9.42*10^22 atoms of He

1.564 * 10^45 moles of He = 9.42*10^22 atoms of He

since we know that at S. T. P, 1 mole of a gas contains 22.4L of the gas

1 mole = 22.4 L

1.564*10^45 moles = (1.564*10^45 * 22.4 L)

= 3.50 * 10^253 L of He atoms.

So therefore, 9.42*10^22 atoms will contain 3.50*10^253 L of Helium gas.