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20 January, 08:54

How many moles are there in

15 grams of:

CaCO3

204 grams of:

Al203

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Answers (1)
  1. 20 January, 09:05
    0
    1) moles = mass/mR

    CaCO3 Mr = 40 + 12 + (16*3)

    = 52 + 48

    = 100

    mass = 15

    so the moles would be 15 : 100

    which is 0.15 moles of CaCO3

    2) moles = mass : Mr

    Mr of Al2O3 = 27 + (16*3)

    = 27 + 48

    = 75

    mass = 204

    so the moles would be 204/75 which is 2.72 moles of Al2O3
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