How many atoms of oxygen are contained in 160 grams of N2O3?

A. 1.27 * 1024

B. 1.81 * 1024

C. 3.80 * 1024

D. 6.28 * 1024

The number of oxygen atoms that are contained in 160 grams of N2O3 are 3.80 x10^24 atoms (answer C)

Explanation

Step 1: calculate the moles of N2O3

moles = mass N2O3 / molar mass N2O3

molar mass of N2O3 = (14 x2) + (16 x3) = 76 g/mol

moles of N2O3 = 160 g / 76 g/mol = 2.105 moles

Step 2: from the moles of N2O3 find the moles of Oxygen

=moles of N2O3 x number of oxygen atoms in N2O3 (3)

= 3 x 2.105 = 6.315 moles

Step 3:use the Avogadro's law to calculate the atoms of oxygen

that is according to Avogadro's law 1 mole = 6.02 x10 ^23 atoms

6.315 moles=? atoms

={ (6.315 moles x 6.02 x10 ^23 atoms) / 1 mole} = 3.80 x10^24 atoms

3.80 * 1024 grams containing