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1 April, 03:09

Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to Question 1 options:

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  1. 1 April, 03:17
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    Reducing the volume of a contained gas by one third, while holding temperature constant, causes pressure to increase by 3.0 times.

    Explanation:

    Boyle's Law : At constant temperature, the volume of a given quantity of a gas varies inversely with its pressure. It is clear from the data that V ∝ 1/P. Also, PV = constant.

    So, for two different values of both P and V:

    ∴ P₁V₁ = P₂V₂.

    ∵ V₂ = 1/3V₁

    ∴ P₂ = P₁V₁/V₂ = P₁V₁ / (1/3V₁) = 3P₁.
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