When the reaction 3 no (g) → n2o (g) + no2 (g) is proceeding under conditions such that 0.015 mol/l of n2o is being formed each second, the rate of the overall reaction is? and the rate of change for no is?

Question

Chemistry

Mitch

29 April, 04:20

When the reaction 3 no (g) → n2o (g) + no2 (g) is proceeding under conditions such that 0.015 mol/l of n2o is being formed each second, the rate of the overall reaction is? and the rate of change for no is?

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Answers (1)

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Mister · Answer 1

1) The rate of the overall reaction = Δ[N₂O]/Δt = 0.015 mol/L. s.

2) The rate of change for NO = - Δ[NO]/Δt = 3 Δ[N₂O]/Δt = 0.045 mol/L. s.

Explanation:

For the reaction:

3NO (g) → N₂O (g) + NO₂ (g).

The rate of the reaction = - 1/3 Δ[NO]/Δt = Δ[N₂O]/Δt = Δ[NO₂]/Δt.

Given that: Δ[N₂O]/Δt = 0.015 mol/L. s.

1) The rate of the overall reaction is?

The rate of the overall reaction = Δ[N₂O]/Δt = 0.015 mol/L. s.

2) The rate of change for NO is?

The rate of change for NO = - Δ[NO]/Δt.

∵ - 1/3 Δ[NO]/Δt = Δ[N₂O]/Δt.

∴ The rate of change for NO = - Δ[NO]/Δt = 3 Δ[N₂O]/Δt = 3 (0.015 mol/L. s) = 0.045 mol/L. s.