3.264g of zonic chloride and 1.468g of zinc metal how much zinc obtained? Was all zinc possible from the recovery?

Question

Chemistry

Leia Ballard

31 December, 05:50

3.264g of zonic chloride and 1.468g of zinc metal how much zinc obtained? Was all zinc possible from the recovery?

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Jaeden Galvan · Answer 1

3.264 g of ZnCl2 is 0.02394 moles. From the formula for ZnCl2, this is also the moles of Zn you should have gotten.

Atomic mass of Zn = 1.565 g is the theoretical yield you should have gotten

percent recovery = 1.468 g / 1.565 g * 100