Ask Question
22 February, 17:33

Jill and Scott both road their bikes for 30 minutes. Jill traveled 5 kilometers and Scott traveled 10. Calculate each person's speed and tell who rode faster. (s=d/t) Question 6 options:

+4
Answers (2)
  1. 22 February, 19:27
    0
    Answer is: Scott rode faster than Jill.

    t (Jill, Scott) = 30 min : 60 min/h.

    t (Jill, Scott) = 0.5 h; Jills and Scott time.

    d (Jill) = 5 km; Jills traveled distance.

    s (Jill) = d (Jill) : t (Jill).

    s (Jill) = 5 km : 0.5 h.

    s (JIll) = 10 km/h; Jills speed.

    s (Scott) = 10 km : 0.5 h.

    s (Scott) = 20 km/h; speed of Scott.
  2. 22 February, 21:10
    0
    I believe that the answer is B. Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h. Because Jill had only gone 5 kilometers vs Scott going a full 10 kileters double what Jill had went.

    Have a nice day!
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Jill and Scott both road their bikes for 30 minutes. Jill traveled 5 kilometers and Scott traveled 10. Calculate each person's speed and ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers