What mass of barium nitrate is dissolved in 21.29 mL of a 3.38 M solution?

18.81 g

Explanation:

We are given;

Volume of Barium nitrate as 21.29 mL or 0.02129 L Molarity of Barium nitrate as 3.38 M

We are required to determine the mass of Barium nitrate

Step 1: Determine the number of moles of Barium nitrate

Number of moles = Molarity * Volume

= 3.38 M * 0.02129 L

= 0.07196 moles

Step 2: Determine the mass of Barium nitrate

We know that;

Mass = Number of moles * Molar mass

Molar mass of Barium Nitrate is 261.337 g/mol

Therefore;

Mass of barium nitrate = 0.07196 moles * 261.337 g/mol

= 18.8058 g

= 18.81 g

Thus, the mass of barium nitrate dissolved is 18.81 g