How many grams of NaC2H3O2 are needed to prepare 350. mL of a 2.75 M solution? (molar mass of

NaC2H3O2 = 82.04 g/mol)

78.96 g of NaC2H3O2

Explanation:

We are given;

Volume of the solution as 350 mL Molarity of the solution as 2.75 M Molar mass of the solute NaC2H3O2 as 82.04 g/mol

We are required to determine the mass of the solute;

First we determine the number of moles;

Moles = Molarity * Volume

Therefore;

Moles of the solute = 2.75 M * 0.350 L

= 0.9625 moles

Second, we determine the mass

Mass = Moles * Molar mass

= 0.9625 moles * 82.04 g/mol

= 78.9635 g

= 78.96 g

Therefore, the mass of NaC2H3O2 needed is 78.96 g