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29 August, 07:46

If a sample of neon gas at 25.00∘C and 0.500 atm is heated at a constant volume until the pressure is 0.850 atm, what must be the final temperature of the gas in Kelvin?

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  1. 29 August, 11:09
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    T₂ = 506.6 K

    Explanation:

    Given dа ta:

    Initial pressure of gas = 25°C (25+273 = 298 K)

    Initial temperature = 0.500 atm

    Final pressure = 0.850 atm

    Final temperature = ?

    Solution:

    According to Gay-Lussac Law,

    The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

    Mathematical relationship:

    P₁/T₁ = P₂/T₂

    Now we will put the values in formula:

    0.500 atm / 298 K = 0.850 atm / T₂

    T₂ = 0.850 atm * 298 K / 0.500 atm

    T₂ = 253.3 atm. K / 0.500 atm

    T₂ = 506.6 K
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