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6 December, 04:49

A sample of gas is in a 5 Liter rigid tank. If the gas has a pressure of 108 Kpa at 20.0 oC, what will be the new temperature at 2.50 atm?

Is it 46.9 K

Is it 413 K

Is it 686 K

Is it - 148 K

Is it 125 K

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Answers (1)
  1. 6 December, 07:24
    0
    T₂ = 687.6 K

    Explanation:

    Given dа ta:

    Initial pressure = 108 Kpa

    Initial temperature = 20°C

    Final temperature = ?

    Final pressure = 2.50 atm

    Solution:

    Initial pressure = 108 Kpa = 108/101 = 1.06588 atm

    Initial temperature = 20°C = 20+273.15 = 293.15 k

    According to Gay-Lussac Law,

    The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

    Mathematical relationship:

    P₁/T₁ = P₂/T₂

    Now we will put the values in formula:

    1.06588 atm / 293.15 K = 2.5 atm/T₂

    T₂ = 2.5 atm * 293.15 K / 1.06588 atm

    T₂ = 732.875 atm. K / 1.06588 atm

    T₂ = 687.6 K
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