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15 July, 21:05

If 0.3041 g of a diprotic solid acid is neutralized by 35.45 ml of 0.0997 m naoh, calculate the malar mass of solid acid

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  1. 15 July, 21:59
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    Number of moles required to neutralize the solution=0.0354*0.0997

    =0.0035mol

    2 mol of NaOH required to neutralize 1 mol of diprotic acid.

    So moles of acid 0.0035/2=0.0017

    Number of moles of acid=Mass of diprotic acid/Molar mass of diprotic acid

    0.0017 = 0.3041/Molar mass of diprotic acid

    Molar mass of diprotic acid=0.3041/0.0017

    =178.8 g/mol
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