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13 September, 09:45

If 38g of sodium hydroxide reacts with 28g of carbon, how many grams of sodium carbonate are produced?

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  1. 13 September, 11:16
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    Mass of sodium carbonate = 33.92 g

    Explanation:

    Given dа ta:

    Mass of sodium hydroxide = 38 g

    Mass of carbon = 28 g

    Mass of sodium carbonate produced = ?

    Solution:

    Chemical equation:

    6NaOH + 2C → 2Na + 3H₂ + 2Na₂CO₃

    Now will calculate the number of moles of reactants:

    Number of moles of sodium hydroxide:

    Number of moles = mass / molar mass

    Number of moles = 38 g / 40 g/mol

    Number of moles = 0.95 mol

    Number of moles of carbon:

    Number of moles = mass / molar mass

    Number of moles = 28 g / 16 g/mol

    Number of moles = 1.75 mol

    Now we will compare the moles of both reactant with sodium carbonate.

    C : Na₂CO₃

    2 : 2

    1.75 : 1.75

    NaOH : Na₂CO₃

    6 : 2

    0.95 : 2/6*0.95 = 0.32

    Number of moles of sodium carbonate produced by sodium hydroxide are less so it will limiting reactant.

    Mass of sodium carbonate:

    Mass = number of moles * molar mass

    Mass = 0.32 mol * 106 g/mol

    Mass = 33.92 g
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