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1 April, 20:58

How many grams of NaF form when. 5 mol of HF reacts with excess Na2SiO3?

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  1. 1 April, 21:34
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    5.25g

    Explanation:

    We'll begin by writing the balanced equation for the reaction. This is shown below:

    Na2SiO3 + 8HF → H2SiF6 + 2NaF + 3H2O

    From the balanced equation above,

    8 moles of HF reacted to produce 2 moles of NaF.

    Therefore, 0.5 moles of HF will react to produce = (0.5 x 2) / 8 = 0.125 mole of NaF.

    Next, we shall convert 0.125 mole of NaF to grams.

    This is illustrated below:

    Mole of NaF = 0.125 mole

    Molar mass of NaF = 23 + 19 = 42g/mol

    Mass of NaF = ... ?

    Mass = mole x molar mass

    Mass of NaF = 0.125 x 42

    Mass of NaF = 5.25g

    Therefore, 5.25g of NaF is produced from the reaction.
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