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26 June, 18:33

A tank holding 7.80 L of gas is at a pressure of 9.80 atm. If the temperature and number of gas particles do not change, what is the new pressure at a volume of 5.3 L?

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A. 14.4 atm

B. 51.9 atm

C. 4.22 atm

D. 0.0693 atm

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  1. 26 June, 21:18
    0
    14.42 atm.

    Explanation:

    We can use the general law of ideal gas: PV = nRT.

    where, P is the pressure of the gas in atm.

    V is the volume of the gas in L.

    n is the no. of moles of the gas in mol.

    R is the general gas constant.

    T is the temperature of the gas in K.

    If n and T are constant, and have two different values of V and P:

    P₁V₁ = P₂V₂

    P₁ = 9.8 atm, V₁ = 7.80 L.

    P₂ = ? atm, V₂ = 5.30 L.

    ∴ P₂ = P₁V₁/V₂ = (9.8 atm) (7.80 L) / (5.30 L) = 14.42 atm.
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