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4 February, 21:45

Calculate the hydrogen-ion concentration (H+] for the aqueous solution in which [OH-1 is 1 x 10-12 mol/L.

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Answers (2)
  1. 5 February, 00:13
    0
    [H+] = 0.01mol/L

    Explanation:

    p[OH] = - log[OH-]

    [OH-] = 1*10^-12

    pOH = - Log[1*10^-12]

    pOH = 12.

    But pH + pOH = 14

    pH = 14 - pOH

    pH = 14 - 12

    pH = 2

    pH = - Log[H+]

    2 = - Log[H+]

    Take the anti log of both sides

    10⁻² = [H+]

    [H+] = 0.01

    The hydrogen ion concentration is 0.01mol/L
  2. 5 February, 00:16
    0
    Answer:If we have [H+][OH-] = Kw = 1.0 x 10^-14

    Then [H+] = Kw / [OH-] = 1.0x 10^-14 / 1 x 10^-11 = 1 x 10^-3 mol/L

    And here is the solution - as you can see it is an acidic one:

    pH = - log [H+] = - log 1 x 10^-3 = 3 < 7
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