The volume of a gas is 59.5 liters at 121 kPa. what will be the volume if the pressure is reduced to 108 kPa, assuming temperature remains the same?

The volume of the gas V2 is 66.67 L

Explanation:

Given data

V1 = 59.5 L

V2=?

T1 = 121K Pa

T2 = 108 K Pa

We have the formula,

V1/T1 = V2/T2

Rewrite the formula as,

V2 = VI T1/T2

V2 = 59.5 L * 121 K Pa/108 K Pa

V2=7199.5 L K Pa / 108 K Pa

V2=66.67 L

The volume of the gas V2 is 66.67 L