Which of the following equations has the correct products and is balanced correctly for a reaction between Na3PO4 and KOH?

A)

Na3PO4 + 3KOH → 3NaOH + K3PO4, because K retains the same charge throughout the reaction

B)

Na3PO4 + KOH → Na3OH + KPO4, because K increases in charge from 1 + to 3 + when it is replaced

C)

Na3PO4 + KOH → 3NaOH + K3PO4, because K retains the same charge throughout the reaction

D)

Na3PO4 + KOH → Na3OH + K3PO4, because K increases in charge from 1 + to 3 + when it is replaced

The answer is: A) Na3PO4 + 3KOH → 3NaOH + K3PO4, because K retains the same charge throughout the reaction.

This chemical reaction is double displacement reaction - cations (K⁺ and Na⁺) and anions (PO₄³⁻⁻ and OH⁻) of the two reactants switch places and form two new compounds.

Na₃PO₄ is sodium phosphate.

KOH is potassium hydroxide.

NaOH is sodium hydroxide.

K₃PO₄ is potassium phosphate.

According to the mass conservation law, there are same number of atoms on both side of balanced chemical reaction.