An average tornado has a pressure of around 630 torr. What is this equivalent to in mmHg, atm and kPa? Show your work.

Question

Chemistry

Singh

16 June, 21:03

An average tornado has a pressure of around 630 torr. What is this equivalent to in mmHg, atm and kPa? Show your work.

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Answers (1)

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Anton Vazquez · Answer 1

1. 630mmHg

2. 0.83atm

3. 83.99KPa

Explanation:

The pressure obtained from the question is 630 torr.

1. The pressure in mmHg is illustrated below:

760torr = 760mmHg

Therefore, 630torr = 630mmHg

2. The pressure in atm is illustrated below:

760torr = 1atm

630torr = 630/760 = 0.83atm

3. The pressure in kPa is illustrated below:

760torr = 101325Pa

630torr = (630x101325) / 760 = 83993.1Pa

But: 1000Pa = 1KPa

83993.1Pa = 83993.1/1000 = 83.99KPa