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14 September, 22:25

A sample of neon gas has a pressure of 2.50 atm in a 2.50 L container, at what volume will

neon have a pressure of 9.68?

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  1. 15 September, 00:49
    0
    0.65L

    Explanation:

    Data obtained from the question include:

    P1 = 2.50atm

    V1 = 2.50L

    P2 = 9.68atm

    V2 = ?

    The new volume can be obtain as follows:

    P1V1 = P2V2

    2.5 x 2.5 = 9.68 x V2

    Divide both side by 9.68

    V2 = (2.5 x 2.5) / 9.68

    V2 = 0.65L
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