Consider the reaction CH4 (g) + 2O2 (g) - > CO2 (g) + 2H2O (g) how many grams of methane should be burned in an excess of oxygen at STP to obtain 5.6 L of carbon dioxide?

2.0 g

4.0 g

16.0 g

32.0 g

CH₄ (g) + 2O₂ (g) - > CO₂ (g) + 2H₂O (g)

22.4 L

22.4 litre of CO₂ is formed by 1 mol of methane

5.6 litre of CO₂ will be formed by 5.6 / 224. mol of methane

= mole of methane required =.25 mol of methane

=.25 x 16 = 4 gram of methane (mol weight of methane = 16 gm)