A sample of argon gas, Ar (g). is placed in a 3.80 L container at 320 K. The gas pressure is 0.496 atm.

How many moles of Ar gas are in the container?

0.0718

n = 0.072 mol

Explanation:

Given dа ta:

Volume of gas = 3.80 L

Temperature of gas = 320 K

Pressure of gas = 0.496 atm

Number of moles of Ar gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P = Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm. L / mol. K

T = temperature in kelvin

Now we will put the values.

n = PV/RT

n = 0.496 atm * 3.80 L / 0.0821 atm. L / mol. K * 320 K

n = 1.88 / 26.27 / mol

n = 0.072 mol