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23 February, 02:45

How many liters of CO2 form at STP if 5.0 g of

CaCO3 are treated with excess hydrochloric acid?

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  1. 23 February, 04:58
    0
    Answer: STP

    CaCO3 = 5 g

    Convert gram to mol

    100 g of CaCO3 = 1 mol

    5 g of CaCO3 (n) = 5 g * (1 mol/100 g) = 0.05 mol

    Gas law

    PV = nRT

    V = nRT/P

    V = (0.05 mol * (0.08206 L atm / K mol) * 273 K) / 1 atm

    V = 1.124 L
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