How many liters of CO2 form at STP if 5.0 g of

CaCO3 are treated with excess hydrochloric acid?

Answer: STP

CaCO3 = 5 g

Convert gram to mol

100 g of CaCO3 = 1 mol

5 g of CaCO3 (n) = 5 g * (1 mol/100 g) = 0.05 mol

Gas law

PV = nRT

V = nRT/P

V = (0.05 mol * (0.08206 L atm / K mol) * 273 K) / 1 atm

V = 1.124 L