A sample of a gas at room temperature occupies a volume of 18.0 L at a pressure of 902 torr. If the pressure changes to 4510 torr, with no change in the temperature or moles of gas, what is the new volume, V2

The correct answer is 3.6 L

Explanation:

According to the gases Boyle's law, the relation between the volume and the pressure of a gas at constant temperature is given by the following mathematical expression:

Pi x Vi = Pf x Vf

Where Pi and Vi are the initial pressure and volume of the gas whereas Pf and Vf are the final pressure and volume, respectively.

In this problem we have:

Vi = 18.0 L

Pi = 902 Torr

Pf = 4510 Torr

The final volume (Vf) will be:

Vf = (Pi x Vi) / Pf = (902 Torr x 18.0 L) / 4510 Torr = 3.6 L

From the result, we can see that if the pressure increases, the volume of the gas decreases.