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9 April, 14:23

1. explain how you would make 100 mL of a 2.0% (w/v) solution of sodium chloride?

2. How many grams of magnesium sulfate are required to make 250 mL of a 1.6% MgSO4 (m/v) solution?

3. A solution contains 2.7 g of CuSO4 in 75 mL of solution. What is the percent (mass/volume) of the solution?

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  1. 9 April, 17:44
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    1.

    Percent (mass/volume) of the solution = (mass of the solute / volume of the solution) x 100

    Given, percent of NaCl (m/v) solution = 2.0 %

    Volume of solution = 100 ml

    Plugging in the numbers in the formula we get,

    2.0 = (mass of NaCl / 100) x 100

    Mass of NaCl = (2.0 x 100) / 100 = 2 g

    So we would dissolve 2g NaCl (s) in 100 ml water to form a 2.0% NaCl solution.

    2.

    Percent (mass/volume) of the solution = (mass of the solute / volume of the solution) x 100

    Given, percent of MgSO₄ (m/v) solution = 1.6%

    Volume of solution = 250 ml

    Plugging in the numbers in the formula we get,

    1.6 = (mass of MgSO₄ / 250) x 100

    Mass of MgSO₄ = (1.6 x 250) / 100 = 4 g

    3.

    Percent (mass/volume) of the solution = (mass of the solute / volume of the solution) x 100

    Given, mass of CuSO₄ = 2.7 g

    Volume of solution = 75 ml

    Percent (mass/volume) of the solution = (2.7 g / 75 ml) x 100 = 3.6%
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