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19 August, 19:28

At 1000 K, the equilibrium constant for the reaction 2NO (g) + Br2 (g) 2NOBr (g) is Kp = 0.013. Calculate Kp for the reverse reaction, 2NOBr (g) 2NO (g) + Br2 (g)

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  1. 19 August, 20:23
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    Kp for the reverse reaction is 76.9

    Explanation:

    Step 1: Kp at 1000 K = 0.013

    Step 2: The balanced equation

    2NO (g) + Br2 (g) ⇆ 2NOBr (g)

    2NOBr (g) ⇆ 2NO (g) + Br2 (g)

    Step 3: Calculate Kp

    Kp for the reaction 2NO (g) + Br2 (g) ⇆ 2NOBr (g)

    Kp = p (NOBr) ² / (pBr2) * (pNO) ²

    Kp = 0.013

    Kp for the reverse reaction 2NOBr (g) ⇆ 2NO (g) + Br2 (g)

    Kp' = (pBr2) * (pNO) ² / p (NOBr) ²

    Kp' = 1/Kp = 1/0.013 = 76.9

    Kp for the reverse reaction is 76.9
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