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17 July, 09:31

Determine the [H+], [OH-], pH, and pOH for

0.045 M HBr

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Answers (1)
  1. 17 July, 10:05
    0
    The answer to your question is below

    Explanation:

    Data

    [HBr] = 0.045 M

    [H⁺] = ?

    [OH⁻] = ?

    pH = ?

    pOH = ?

    Process

    1. - Determine the [H⁺]

    The [H⁺] is equal to the [HBr] then, [H⁺] = 0.045 M

    2. - Determine the pH

    pH = - log[H⁺]

    -Substitution

    pH = - log[0.045]

    -Result

    pH = 1.35

    3. - Determine the pOH

    Formula

    pH + pOH = 14

    -Solve for pOH

    pOH = 14 - pH

    -Substitution

    pOH = 14 - 1.35

    -Result

    pOH = 12.65

    4. - Determine the [OH⁻]

    pOH = - log[OH⁻]

    -Solve for [OH⁻]

    [OH⁻] = antilog (-pOH)

    -Substitution

    [OH⁻] = antilog (-12.65)

    -Result

    [OH⁻] = 2.22 x 10⁻¹³
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