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5 September, 15:32

How many kilograms of oxygen did Samantha need to utilize to react with 36.29 kg of triglycerides (C55H104O6) ?

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  1. 5 September, 17:47
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    105.33Kg of O2.

    Explanation:

    Step 1:

    The balanced equation for the reaction. This is given below:

    C55H104O6 + 78O2 - > 55CO2 + 52H2O

    Step 2:

    Determination of the masses of C55H104O6 and O2 that reacted from the balanced equation.

    This is illustrated below:

    Molar mass of C55H104O6 = (12x55) + (104x1) + (16x6) = 860g/mol

    Mass of C55H104O6 from the balanced equation = 1 x 860 = 860g.

    Divide the mass of C55H104O6 by 1000 to express in kg i. e

    Mass of C55H104O6 = 860/1000 = 0.86Kg

    Molar Mass of O2 = 16x2 = 32g/mol

    Mass of O2 from the balanced equation = 78 x 32 = 2496g.

    Divide the mass of O2 by 1000 to express in kg i. e

    Mass of O2 = 2496/1000 = 2.496kg.

    From the balanced equation above,

    0.86kg of C55H104O6 reacted with 2.496Kg of O2.

    Step 3:

    Determination of the mass of O2 in kg needed to react with 36.29 kg of triglycerides (C55H104O6).

    This can be obtained as follow:

    From the balanced equation above,

    0.86kg of C55H104O6 reacted with 2.496Kg of O2.

    Therefore, 36.29 kg of C55H104O6 will react with = (36.29 x 2.496) / 0.86 = 105.33Kg of O2.

    Therefore, 105.33Kg of O2 is needed for the reaction.
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