What mass of H2SO4 is contained in 60.00 mL of a 5.85 M solution of sulfuric acid

First, we have to calculate the number of moles of H2SO4 in the solution:

V=60 mL = 0.06 L

c=5.85 mol/L

n=V*c=0.06*5.85=0.351 mol

Then we need to find the molar mass of H2SO4:

2*Ar (H) + Ar (S) + 4*Ar (O) =

=2 + 32 + 64 = 98 g/mol

Finally, we need to find the mass of H2SO4:

m=0.351 * 98 = 34.398 g