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10 June, 08:43

How many mL of a 2.50 M NaOH solution are required to make a 525 mL of a 0.150 M NaOH solution?

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  1. 10 June, 11:11
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    V₁ = 31.5 mL

    Explanation:

    Given dа ta:

    Initial molarity = 2.50 M

    Initial volume required = ?

    Final molarity = 0.150 M

    Final volume = 525 mL

    Solution:

    Formula:

    M₁V₁ = M₂V₂

    M₁ = Initial molarity

    V₁ = Initial volume

    M₂ = Final molarity

    V₂ = Final volume

    Now we will put the values in formula.

    2.50 M * V₁ = 0.150 M * 525 mL

    V₁ = 0.150 M * 525 mL / 2.50 M

    V₁ = 78.75 M. mL / 2.50 M

    V₁ = 31.5 mL
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