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19 June, 12:00

How many moles of oxygen are in a

7.68 L container at 355 K and exerting a

pressure of 8.57 atm on the walls of the

container?

+4
Answers (1)
  1. 19 June, 15:50
    0
    Rearrange the ideal gas law to solve for n:

    n = (PV / RT)

    = (8.57 atm * 7.68 L) / {[ (0.082057 L • atm) / (mol • K) ] * 355 K}

    = 2.26 moles
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