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3 July, 12:58

The titration of 25.0 mL of an unknown concentration H2SO4 solution requires 83.6 mL of 0.12 M LiOH solution. What is the concentration of the H2SO4 solution (in M)

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  1. 3 July, 14:07
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    0.20M

    Explanation:

    First let us generate a balanced equation for the reaction. This is illustrated below:

    H2SO4 + 2LiOH - > Li2SO4 + 2H2O

    From the equation above,

    nA (mole of the acid) = 1

    nB (mole of the base) = 2

    Data obtained from the question include:

    Ma = ?

    Va = 25.0mL

    Mb = 0.12 M

    Vb = 83.6 mL

    The concentration of the acid can be obtain as follows:

    MaVa/MbVb = nA/nB

    Ma x 25 / 0.12 x 83.6 = 1/2

    Cross multiply to express in linear form as shown below:

    Ma x 25 x 2 = 0.12 x 83.6

    Ma x 50 = 10.032

    Divide both side by 50

    Ma = 10.032/50

    Ma = 0.20M

    The concentration of the acid is 0.20M
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