a propane tank containing 55l has 2.46 moles of the gas C3 is propane what would the number of moles if 1/2 of the gas is used

Answer;

= 1.23 moles

Explanation;

V1/n1 = V2/n2

V1 = 55 L, n1 = 2.46 moles

1/2 of the gas was used and thus; 1/2 or 27.5 L remained.

Therefore;

55 L/2.46 moles = 27.5 L / n2

n2 = (2.46 * 27.5) / 55

= 1.23 moles