For a 0.00554 mol sample of H2, P=23.44 torr and T=557 K. What is its volume?

The volume is 8,22 liters.

Explanation:

The unit of pressure (from Torr to atm) must be converted: 760 Torr = 1 atm

760 Torr---1 atm

23,44Torr--x = (23,44Torr x 1 atm) / 760 Torr = 0,0308 atm

PV=nRT V = (nRT) / P

V = (0,00554 mol x 0,082 l atm/K mol x 557 K) / 0,0308 atm

V=8, 22 L