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28 August, 15:03

If a gas has a volume of 15l and a temperature of 125K, and the temperature is increased to 225K, what is the new volume

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  1. 28 August, 16:41
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    V₂ = 27 L

    Explanation:

    Given dа ta:

    Initial volume = 15 L

    Initial temperature = 125 K

    Final temperature = 225 K

    Final volume = ?

    Solution:

    The given problem will be solve through the Charles Law.

    According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

    Mathematical expression:

    V₁/T₁ = V₂/T₂

    V₁ = Initial volume

    T₁ = Initial temperature

    V₂ = Final volume

    T₂ = Final temperature

    Now we will put the values in formula.

    V₁/T₁ = V₂/T₂

    V₂ = V₁T₂/T₁

    V₂ = 15 L * 225K / 125 k

    V₂ = 3375 L. K / 125 K

    V₂ = 27 L
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