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26 April, 06:59

At a certain temperature, the pHpH of a neutral solution is 7.45. What is the value of KwKwK_w at that temperature? Express your answer numerically using two significant figures. View Available Hint (s)

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  1. 26 April, 07:38
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    The value of Kw is 1.26 * 10^-15

    Explanation:

    Step 1: Data given

    The pH of the neutral solution = 7.45

    pH = - log[H+]

    Kw = [OH-][H+]

    Step 2: Calculate [H+]

    pH = 7.45

    -log[H+] = 7.45

    [H+] = 10^-7.45

    [H+] = 3.55 * 10^-8 M

    Step 3: Calculate [OH-]

    Since pH and pOH are equal in our neutral solution so are [H+] = [OH-]

    [OH-] = 3.55 * 10^-8 M

    Step 4: Calculate Kw

    Kw = [H]*[OH]

    Kw = 3.55 * 10^-8 M * 3.55 * 10^-8 M

    Kw = (3.55 * 10^-8) ²

    Kw = 1.26 * 10^-15

    The value of Kw is 1.26 * 10^-15
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