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26 February, 19:59

How many moles of chlorine are used up in a reaction that produces 0.35kg of BCl3

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  1. 26 February, 23:52
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    4.48 mol Cl2. A reaction that produces 0.35 kg of BCl3 will use 4.48 mol of Cl2.

    (a) The balanced chemical equation is

    2B + 3Cl2 → 2BCl3

    (b) Convert kilograms of BCl3 to moles of BCl3

    MM: B = 10.81; Cl = 35.45; BCl3 = 117.16

    Moles of BCl3 = 350 g BCl3 x (1 mol BCl3/117.16 g BCl3) = 2.987 mol BCl3

    (c) Use the molar ratio of Cl2:BCl3 to calculate the moles of Cl2.

    Moles of Cl2 = 2.987 mol BCl3 x (3 mol Cl2/2 mol BCl3) = 4.48 mol Cl2
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