How many grams of Co are needed to react with an excess of fe203 to produce 156.2 g FE? show your work.

fe203 (S) + 3 CO (g) 3 CO2 (g) 2 fe (s)

The reaction is given as

Fe2O3 (s) + 3CO (g) - -->3CO2 (g) + 2Fe (s)

No. of moles=mass in gram/molar mass

As for Fe mole = 156.2g/55.847=2.7969~2.797

The ratio b/w CO and Fe is 3:2

Moles of CO needed = 2.797x3/2=4.1955

Mass of CO needed = 4.195mol x 28.01g/mol = 117.515g