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29 January, 05:00

Use the specific heat capacity that you calculated for granite to determine how many grams of granite at the initial temperature of 80 °C must mix with 3,000 g of water at the initial temperature of 20 °C to result in a final system temperature of 20.45 °X. (Hunt: Start by calculating how much heat energy is needed to change the water's temperature by 0.45 °C). Show your work. Use the Gizmo to check your answer.

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  1. 29 January, 05:32
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    specific heat of granite s =.79 J / g / k

    let the mass of granite = m

    heat lost by granite = heat gained by water

    heat lost = mass x specific heat x drop in temperature

    = m x. 79 x (80 - 20.45)

    heat gained by water

    = 3000 x 4.186 x (20.45 - 20)

    heat lost by granite = heat gained by water

    m x. 79 x 59.55 = 3000 x 4.186 x. 45

    m = 120.12 g.
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