A bubble of helium gas has a volume of 0.65 L near the bottom of a large

aquarium where the pressure is 3.4 atm and the temperature is 19°C. Determine

the bubble's volume upon rising near the top where the conditions change to 3.2

atm and 36°C.

0.73L

Explanation:

The following data were obtained from the question:

V1 = 0.65 L

P1 = 3.4 atm

T1 = 19°C = 19 + 273 = 292K

V2 = ?

P2 = 3.2 atm

T2 = 36°C = 36 + 273 = 309K

The bubble's volume near the top can be obtain as follows:

P1V1 / T1 = P2V2 / T2

3.4 x 0.65/292 = 3.2 x V2 / 309

Cross multiply to express in linear form as shown below:

292 x 3.2 x V2 = 3.4 x 0.65 x 309

Divide both side by 292 x 3.2

V2 = (3.4 x 0.65 x 309) / (292 x 3.2)

V2 = 0.73L

Therefore, the bubble's volume near the top is 0.73L